If log 2 = x; log 3 = y and log 7 = z, then find the value of \log (4 . \sqrt^3 63 ) .

Logarithms Practice Test 1

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If log 2 = x; log 3 = y and log 7 = z, then find the value of

\log (4 . √^3 63 )

Solution:

\log (4 . √^3 63 )

=\log4+1/3\log63

=\log4+1/3\log(3^2×7)

=\log2^2+1/3(2\log 3+\log 7)

=2\log 2+2/3\log 3+1/3\log 7

=2x+2/3y+1/3z

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