Decimals and Fractions Practice Test 1

Here, $47.2506=4\mathit{A}+\frac{7}{\mathit{B}}+2\mathit{C}+\frac{5}{\mathit{D}}+6\mathit{E}$...(i)
But, 47.2506 = 40 + 7 + 0.2 + 0.05 + 0.0006 ...(ii)
By comparing (i) and (ii), we get
$4\mathit{A}=40\Rightarrow \mathit{A}=10$;
$\frac{7}{\mathit{B}}=7\Rightarrow \mathit{B}=1$;
$2\mathit{C}=0.2\Rightarrow \mathit{C}=0.1$
$\frac{5}{\mathit{D}}=0.05\Rightarrow \mathit{D}=100$;
$6\mathit{E}=0.0006\Rightarrow \mathit{E}=0.0001$
Now, $5\mathit{A}+3\mathit{B}+6\mathit{C}+\mathit{D}+3\mathit{E}$ = 5 × 10 + 3 × 1 + 6 × 0.1 + 100 + 3 × 0.0001
= 50 + 3 + 0.6 + 100 + 0.0003 = 153.6003