Average Practice Test 6

Let the eight consecutive numbers are (x), (x + 1), (x + 2), (x + 3), (x + 4), (x + 5), (x + 6), (x + 7)
Average of middle terms = 6
$\frac{\left(\mathit{x}+3\right)+\left(\mathit{x}+4\right)}{2}=6$
$\mathit{x}+3+\mathit{x}+4=12$
$2\mathit{x}+7=12$
$2\mathit{x}=5$
$\mathit{x}=\frac{5}{2}=2.5$
So, the eight consecutive numbers are; 2.5, 3.5, 4.5, 5.5, 6.5, 7.5, 8.5, 9.5
Sum of eight consecutive numbers = 48