NTSE Stage 2 SAT 2016 Question Paper

Question : 58 of 100

Marks: +1, -0

If the line segment joining (2, 3) and (–1, 2) is divided internally in the ratio 3 : 4 by the graph of the equation

\x + 2\y = \k

, the value of k is

Solution:

\a={-3+8}/{3+4}

=5/7({\mx_2+\nx_1}/{\m+\n})

\b={6+12}/7=18/7({\my_2+\ny_1}/{\m+\n})

\x + 2\y = \k

5/7+2×18/7=\k

5/7+36/7=\k

41/7=\k

So the value of k is

41/7

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