NTSE Stage 2 SAT 2016 Question Paper

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Question : 57 of 100

Marks: +1, -0

The centre of the circle passing through the points (6, –6), (3, –7) and (3, 3) is

(3, 2)
(–3, –2)
(3, –2)
(–3, 2)

Solution:

(x -6)^2 + (y + 6)^2 = (x – 3)^2 + (y + 7)^2

...(1)

(x -3)^2 + (y – 3)^2 = (x - 3)^2 + (y +7)^2

\y ^2 - 6y + 9 = \y^2 + 14\y + 49

-20\y = 40

put

\y = –2

in equation (1)

(x – 6)^2 + (4)^2 = (x- 3)^2 + (5)^2

-6x = - 18

x = 3

So the centre of the circle is (3, –2)

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