NTSE Stage 2 MAT 2019 Exam Question Paper

Question : 10 of 100

Marks: +1, -0

If CLOUD =11, BURST = 16 and ACE = 3, then MONSOON = ?

Solution:

\;\;{\;\text"Sum of place value of letters"\;}/{\;\text"Number of letters"\;}

As,

{\CLOUD}=\;\;{(3+12+15+21+4)}/{5}

=55/5=11

\;\text"BURST"\;=\;\;{(2+21+18+19+20)}/{5}

=80/5=16

\ACE=\;\;{1+3+5}/{3}=3

Similarly,

{\MONSOON}=\;\;{13+15+14+19+15+15+14}/{7}

=105/7=15

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