NIMCET 2019 Question Paper with solutions

Question : 58 of 120

Marks: +1, -0

Two liquid A and B are int he ratio5 : 1 inc ontainer 1 and 1 : 3 in container 2 respectively. In what ratio should the content of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1:1?

2 : 3
4 : 3
3 : 2
3 : 4

Validate

Solution:

Let both container mixed in

x:1

. Then
According to the question.

{\;\;{5x}/{6}+\;\;{1}/{4}}/{\;\;{x}/{6}+\;\;{3}/{4}}=\;\;{1}/{1}⇒\;\;{5x}/{6}+\;\;{1}/{4}=\;\;{x}/{6}+\;\;{3}/{4}

⇒\;\;{5x}/{6}-\;\;{x}/{6}=\;\;{3}/{4}-\;\;{1}/{4}⇒\;\;{4x}/{6}=\;\;{2}/{4}

∴\;x=\;\;{12}/{16}=\;\;{3}/{4}

∴ Required ratio

=x:1=3/4:1=3:4

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