NIMCET 2018 Question Paper with solutions

Area of parallelogram ABCD = 208 $\mathit{x}{\mathit{m}}^2$
Area of parallelogram = Base x Height
Let height of parallelogram ABCD be h.
∴ h × 13 = 208
∴ h = 16 cm
Now, height of parallelogram ABEF = Height ofparallelogram ABCD
∴ Required height = 16 cm