NIMCET 2015 Question Paper with solutions

Question : 52 of 120

Marks: +1, -0

Using only 2, 5, 10, 25 and 50 paise coins, what is the smallest number of coins required to pay exactly 78 paise, 69 paise and Rs. 1.01 to three different persons ?

Validate

Solution:

Here,
We have, to find LCM of 78 paise, 69 paise and 101 paise. And

78=1×50+2×10+2×4=5

coins

69=1×50+1×10+1×5+2×2=5

101=1×101=1×50+4×10+1×5+3×2=9

So LCM

=2×3×13×23×101=181194

Go to Question:

Prev Question

Next Question