NIMCET 2015 Question Paper with solutions

Question : 51 of 120

Marks: +1, -0

How many 3-digit numbers divisible by 5, can be formed using the digits 2, 3, 5, 6, 7 and 9, without repetition of digits ?

Solution:

Here

↓

\;\;↓

\;\;5\;\;\;5

is fixed
So, total 3 digits number divisible by 5

=5×4×1=20

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