NIMCET 2014 Question Paper with solutions

Question : 36 of 120

Marks: +1, -0

A box contains 3 coins, one coin is fair, one coin is two headed and one coin is weighted, so that the probabilityof heads appearing is

1/3

. A coin is selected at random and tossed, then the probability that head appears, is

Solution:

Probability of choosing fair coin =

1/3

Probability of choosing two headed coin =

1/3

Probability of choosing weighted coin =

1/3

∴ Required probability =

1/3×1/2+1/3×1+1/3×1/3

1/6+1/3+1/9

{3+6+2}/{18}

{11}/{18}

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