NIFT UG 2020 Question Paper with solutions

Let the weight of 12 th person $=\mathit{x}\mathit{k}\mathit{g}$
Let the average weight of 12 persons $=\mathit{y}\mathit{k}\mathit{g}$
According to the question, $\frac{11\times 95+\mathit{x}}{12}=\mathit{y}$
$\Rightarrow 1045+\mathit{x}=12\mathit{y}$.....(i)
Again, according to the question,
$\mathit{x}=\mathit{y}+33$
$1045+\mathit{y}+33=12\mathit{y}$ [from Eq. (i)]
$\Rightarrow 11\mathit{y}=1078\Rightarrow \mathit{y}=98$
$\therefore$ Weight of 12 th person $=\mathit{y}+33$
$=98+33=131\mathit{k}\mathit{g}$