NIFT UG 2020 Question Paper with solutions

Question : 14 of 150

Marks: +1, -0

Let

x

be the smallest number, which when added to 2000 makes the resulting number divisible by 12,16,18 and

21 .

The sum of the digits of

x

Solution:

LCM of 12,16,18 and

21=1008

Divisible number

=2016

So, 16 is required

∴

Sum of digits

=1+6=7

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