NIFT UG 2019 Question Paper with solutions

Total amount to be distributed $=\mathit{₹}730$
From the given question.
Ratio of $\mathit{A}$ and $\mathit{B}=3:4$.....(i)
And ratio of $\mathit{B}$ and $\mathit{C}=3.5:3$
$=7:6$....(ii)
From Eqs. (i) and (ii) ratio of $\mathit{A}:\mathit{B}:\mathit{C},$ we get
$=\left(3\times 7\right):\left(4\times 7\right):\left(6\times 4\right)$
$=21:28:24$
Now, the share of $\mathit{B}$ exceeds that of $\mathit{C}$
$=($ Share of $\mathit{B})-($ Share of $\mathit{C})$
$=\frac{28-24}{21+28+24}\times 730$
$=\frac{4}{73}\times 730$
$=4\times 10=\mathit{₹}40$
Hence, B gets $\mathit{₹}40$ more than $\mathit{C}$.