NIFT PG 2013 Question Paper with solutions

Question : 58 of 150

Marks: +1, -0

A number when divided by a certain divisor gives remainder 241, when twice the number was divided by the same divisor, the remainder was 112. What will be the divisor?

Validate

Solution:

Let divisor is d
Then,

2×241–112=d

d=482–112=370

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