NIACL Model Paper 9 with solutions for free online practice

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Question : 33 of 100

Marks: +1, -0

126÷14 ×(9)^2-53={(?)}^2

$26$
$√26$
$-729$
$27$
$√27$

Solution:

1)

126/14× 9^2-53 = (?)^2

⇒

9 × 9^2 - 53 = (?)^2

⇒

(?)^2 = 729 - 53 = 676

⇒

? =√676 = 26

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