NIACL Model Paper 9 with solutions for free online practice

© examsiri.com

Question : 32 of 100

Marks: +1, -0

(16 ×4)^3÷(4)^5×(2×8)^2=(4)^{?}

5
6
3
8
None of these

Solution:

(4)

(16 × 4)^3 ÷ (4)^5× (2 × 8)^2 = 4^{?}

=>

(4^3)^3 - (4)^5 × (4^2)^2 = 4^{?}

=>

4^9÷ 4^5 × 4^4 = 4^{?}

=4^{9-5+4} = 4^{? }

=>

4^8 = 4^{?}⇒ ? = 8

© examsiri.com

Go to Question:

Prev Question

Next Question