NIACL Model Paper 6 with solutions for free online practice

Question : 49 of 100

Marks: +1, -0

Boat ‘A’ can travel 25.5 km downstream in 1 hour 30 minutes, when the speed of the river current is 4.5 kmph. How much distance can boat ‘B’ cover in 2 hours 48 minutes while travelling upstream, if its speed in still water is 2 kmph more than the speed of boat ‘A’ in still water ? (considering that the speed of the current is the same)

24 km
28 km
18 km
20 km
None of these

Validate

Solution:

(2) 1 hour 30 minutes

=3/2

hours
∴Rate downstream of boat A

={25.5}/3/2

{ 25.5 ×2}/3=17

kmph
Speed of boat A in still water
=

17-4.5 = 12.5

kmph
∴ Speed of boat B in still water
= (1 2.5 + 2) kmph = 14.5 kmph
∴ Rate upstream of boat B
= 14.5 - 4.5 = 1 0 kmph
2 hours 48 minutes

=[2+48/60]

hours

=14/5

hours
∴Required distance

=14/5×10=28

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