The ratio between the height of tower and the point at some distance is 5 \sqrt{3}: 5. What will be the angle of elevation?

NCHMCT JEE 2021 Question Paper with solutions for online practice

Question : 80 of 200

Marks: +1, -0

The ratio between the height of tower and the point at some distance is

5 √{3}: 5

. What will be the angle of elevation?

Solution:

(b) Let, height of tower

=5 √{3 x}

and distance of point

=5 x

Let, angle of elevation

=θ

Then, In

△ A B C

\tan θ=\;{A C}/{B C}

⇒ \tan θ=\;{5 √{3} x}/{5 x}=√{3}

⇒ \tan θ=√{3}=\tan 60^{∘}

⇒ θ=60^{∘}

Go to Question:

Prev Question

Next Question