NCHMCT JEE 2019 Question Paper with solutions for online practice

Question : 13 of 200

Marks: +1, -0

A number less than 100, when divided by 2, 3, 4 and 5 leaves remainder 1 in each case.The number is :

Solution:

A number divided by 2, 3, 4 and 5
= LCM (2, 3, 4, 5)
= 60
∵ Remainder left in each case = 1
∴ Required number

= 60 + 1 = 61 (< 100)

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