\int \frac{\log (x^2+a^2) }{x^2} \dx=

Correct Answer is : −log(x2+a2)x+2atan−1xa+c, where c is a constant of integration.

\frac{-\log (x^2+ {\a}^2) }{x}+\frac{1}{ {\a}} \tan ^{-1} \frac{x}{ {\a}}+ {\c}, where {\c} is a constant of integration.

\frac{-\log (x^2+ {\a}^2) }{x}+\frac{2}{ {\a}} \tan ^{-1} \frac{x}{ {\a}}+ {\c}, where {\c} is a constant of integration.

\frac{\log (x^2+ {\a}^2) }{x^2}-\frac{1}{ {\a}} \tan ^{-1} \frac{x}{ {\a}}+ {\c}, where {\c} is a constant of integration.

\frac{\log (x^2+ {\a}^2) }{x^2}-\frac{2}{ {\a}} \tan ^{-1} \frac{x}{ {\a}}+ {\c}, where {\c} is a constant of integration.

MHTCET 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 58 of 150

Marks: +1, -0

∫‌

log(x2+a2)

‌dx=

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