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Question : 57 of 150
Marks:
+1,
-0
Solution:
b+c=(2‌+λ)−2+2‌ Unit vector ‌‌=‌‌=‌| (2+λ)−2+2 |
| √(2+λ)2+(−2)2+22 |
‌=‌| (2+λ)−2+2 |
| √λ2+4λ+12 |
According to the given condition,
‌(+2+)⋅(‌| (2+λ)−2+2 |
| √λ2+4λ+12 |
)=1‌⇒‌| (2+λ)−4+2 |
| √λ2+4λ+12 |
=1‌⇒λ=√λ2+4λ+12‌⇒λ2=λ2+4λ+12‌⇒4λ=−12‌⇒λ=−3
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