Management Aptitude Test Sep 2020 Paper

Question : 120 of 200

Marks: +1, -0

A cistern contains

50 {L}

of water.

5 {L}

of water is taken out of it and replaced with wine. The process is repeated again. Find the proportion of wine and water in the resulting mixture.

Solution:

After

5 {L}

water taken out, remaining water

=50-5=45 {L}

∵

Water is replaced with wine.

∴

Quantity of wine

=5 {L}

Now, in next step same process is done and

10 \%

of water and

10 \%

of wine take out from mixture.

∴

In mixture, remaining water

=45-4.5=40.5 {L}

and remaining wine

=5-0.5=4.5 {L}

Now,

5 {L}

of wine is added.
So, total quantity of wine in final mixture

=4.5+5=9.5 {L}

and remaining water in final mixture

=40.5 {L}

∴

Required ratio

=9.5: 40.5

=95: 405=19: 81

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