Management Aptitude Test Sep 2020 Paper

Question : 118 of 200

Marks: +1, -0

The horizontal distance between two towers is

60 {m}

. The angular elevation of the top of the taller tower as seen from the top of the shorter one is

30^{∘}

. If the height of the taller tower is

150 {m}

, the height of the shorter one is

Solution:

Let the height of shorter tower be

h {m}

.
Let

A B

be shorter tower and

C D

be the taller one.

△ A E C, \tan 30^{∘}=\;{C E}/{A E}

\;{1}/{√{3}} \;\; =\;{150-h}/{60}

⇒ \;\; 150-h \;\; =\;{60}/{√{3}}

⇒ \;\; h \;\; =150-20√{3}

\;\; ≈ 116 {m}

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