Management Aptitude Test Sep 2011 Paper

Question : 88 of 200

Marks: +1, -0

A hemispherical bowl of thickness 1 cm and external diameter 10 cm is to be painted all over. What is the cost of painting at the rate of ₹ 0.70 per

cm^2

Solution:

(1) Let

r_1=10/2

= 5 cm
and

r_2=8/2

= 4 cm
∴ Area to be painted

= 2π

r_1^2

+ 2π

r_2^2

+ (π

r_1^2

- π

r_2^2

)
= 3π

r_1^2

+ π

r_2^2

= π (

3r_1^2

r_2^2

)

22/7

[3 x 25 + 16] =

22/7

x 91

cm^2

∴ cost of painting = ₹

22/7

x 91 x 0.71 = ₹ 200.2 = ₹ 200

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