Management Aptitude Test Feb 2012 Paper

Question : 105 of 200

Marks: +1, -0

Two pipes A and B can fill a cistern in 12 min and 15 min, respectively, while a third pipe C can empty it in 6 min. Both A and B pipes are opened together for 5 min in the beginning and then the third pipe C is also opened. In what time will the cistern be emptied?

30 min
33 min
37.5 min
45 min

Validate

Solution:

(4) Part of cistern that is filled by A and B in 5 min
= 5

(1/12+1/15)=3/4

Now, the time taken to empty the cistern, when all the pipes are opened
=

1/{1/6-1/12+1/15}

1/{{10-5-4}/60}

= 60 min
∴ Time taken to empty

3/4

part of the cistern =

3/4

x 60 = 45 min

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