Management Aptitude Test Dec 2013 Paper

Question : 102 of 200

Marks: +1, -0

Suppose that a maximum of 25 g of salt dissolves in 100 g of water. Any more salt, if added, remains undissolved and a sediment falls at the bottom. Now, water is evaporated from 1 kg of a 4% solution at the rate of 28 g per hour. After how long will it start sedimenting, approximately?

29 h
31 h
35 h
23

Validate

Solution:

(b) Maximum 25 g of salt dissolves in 100 g water, after that sedimentation start.
Amount of salt in given solution = 1000 x

4/100

= 40 g
∴ Minimum amount of water required after which 40 sedimentation starts = 40/25$$ x 100 = 160g
∴ Minimum 840 g needs to evaporated.
Time required to evaporated 840 g of water =

840/28

= 30h
∴ After 31 h, the given solution starts sedimenting.

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