Management Aptitude Test Dec 2013 Paper

(a) Let the co st of computer system be ₹ x and cost of colour printer be ₹ y
Then, according to the question,
x + y = $\frac{90}{100}\mathit{x}+\frac{120}{100}\mathit{y}$
⇒ 10x - 2y = 0    ....(i)
and (x + y) - 800 = $\frac{105}{100}\mathit{x}+\frac{85}{100}\mathit{y}$
⇒ $-\frac{5}{100}\mathit{x}+\frac{15}{100}\mathit{y}$ = 800
⇒ - x + 3y = 16000    .....(ii)
On solving Eqs. (i) and (ii), we get
y = 16000, x = 32000
∴ Cost of colour printer = ₹ 16000