Management Aptitude Test 2018 Paper

(c) Let the CP of Bike-1 and Bike-2 be ₹ x and ₹ y.
Then, $\frac{120}{100}\mathit{x}$= 24000
⇒ x = ₹ 20000
and $\frac{85}{100}$ y = 24000
⇒ y = ₹ 28235.29 ⇒ y = ₹ 28235
Total SP of two bikes = ₹ (24090 x 2) = ₹ 48000
Total CP of two bikes = ₹ 48235
Now, gain/loss per cent = $\frac{48000-48235}{48235}$ x 100
= -$\frac{235}{48235}$ x 100 = - $\frac{20}{41}$
Hence, loss per cent is $\frac{20}{41}$ %.