Management Aptitude Test 2018 Paper

(b) Area of square = 33 $\mathit{c}{\mathit{m}}^2$
⇒ ${\left(\mathrm{side}\right)}^2$ = 33 ⇒ side = $\sqrt{33}$ cm
Perimeter of square = Circumference of circle
⇒ 4 x $\sqrt{33}$ = 2πr [Let radius of circle be r cm]
⇒ r = $\frac{4\sqrt{33}}{2\mathit{\pi }}$ cm
∴ Area of circle = $\mathit{\pi }{\mathit{r}}^2$ = π × $\frac{4}{2\mathit{\pi }}\sqrt{33}$ × $\frac{4}{2\mathit{\pi }}\sqrt{33}$ = 42 $\mathit{c}{\mathit{m}}^2$