Management Aptitude Test 2015 Paper

(d) Here, girls = 55%
and boys = (100 - 55) = 45%
Let total students be x
According to the question,
80% of boys are present,
∴ Number of boys
= $\frac{80}{100}\mathrm{of}\frac{45}{100}\mathrm{of}\mathit{x}$
= $\frac{8}{10}\times \frac{45}{100}\times \mathit{x}$
= $\frac{36}{100}\mathrm{of}\mathit{x}$
Since, total students present on that day is 70%.
Number of girls
= 70% of x - $\frac{36}{100}\mathrm{of}\mathit{x}$
= $\frac{\left(70-36\right)\mathit{x}}{100}$
= $\frac{34}{100}\mathrm{of}\mathit{x}$
= 34% of total students