Management Aptitude Test 2014 Paper

(a ) (A + B)'s one day work = $\frac{1}{5}$
⇒ (A + B) = $\frac{1}{5}$ .......(i)
By given condition,
2A + $\frac{1}{2}$ B = $\frac{1}{4}$ .......(ii)
On multiplying Eq. (i) by $\frac{1}{2}$ we get
$\frac{1}{2}\mathit{A}+\frac{1}{2}\mathit{B}=\frac{1}{10}$ ....(iii)
On Eq. (iii) subtracted from Eq. (ii), we get
  2A+ $\frac{1}{2}$ B = $\frac{1}{4}$
$\frac{1}{2}\mathit{A}+\frac{1}{2}\mathit{B}=\frac{1}{10}$
-       -             -

  $\left(2-\frac{1}{2}\right)\mathit{A}=\frac{1}{4}-\frac{1}{10}$
⇒ $\frac{3}{2}\mathit{A}=\frac{5-2}{20}$
⇒ $\frac{3}{2}\mathit{A}=\frac{3}{20}$
⇒ $\frac{\mathit{A}}{2}=\frac{1}{20}$
∴A = 10
Hence. A alone would do that work in 10 days.