A cistern contains 50 L of water. 5 L of water is taken out of it and replaced with wine. The process is repeated again. Find the proportion of wine and water in the resulting mixture.
(c) After 5 L water taken out, remaining water = 50 - 5 = 45 L ∵ Water is replaced with wine. ∴ Quantity of wine = 5 L Now, in next step same process is done and 10% of water and 10% of wine take out from mixture. ∴ In mixture, remaining water = 45 - 4.5 = 40.5 L and remaining wine = 5 - 0.5 = 4.5 L Now, 5 L of wine is added. So, total quantity of wine in final mixture = 4.5 + 5 = 9.5 L and remaining water in final mixture = 40.5 L ∴ Required ratio = 9.5 : 40.5 = 95 : 405 = 19 : 81