Madhya Pradesh Police Exam Model Paper 9

Question : 54 of 100

Marks: +1, -0

Given ∠POR = 3x° and ∠QOR = 2x° + 10°. If POQ is a straight line, then the value of 3x° + 10° is:

Solution:

Given:
∠POR = 3x°
∠QOR = 2x° + 10°
Concept used:
Sum of all the angles formed on a straight line is 180°
Calculation:

∠POQ = ∠POR + ∠QOR

⇒ 180° = 3x° + 2x° + 10°

⇒ 180° = 5x° + 10°

⇒ 5x° = 170

⇒ x = 34°

Value of

3x° + 10° = (3 × 34) + 10° = 112°

∴ The value of $3x° + 10°$ is 112°

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