Madhya Pradesh Police Exam Model Paper 7

Given:
Two angles of a right angled triangle other than right angle are $\left(5\mathit{x}+9\right)°$ and $\left(9\mathit{x}+11\right)°$ .
Formula:
Sum of two angles of a right angled triangle other than right angle is 90°.
Calculation:
According to the question
$\left(5\mathit{x}+9\right)°+\left(9\mathit{x}+11\right)°=90°$
$\Rightarrow 5\mathit{x}+9+9\mathit{x}+11=90°$
$\Rightarrow 14\mathit{x}=90°-20°$
$\Rightarrow \mathit{x}=70°/14$
$\therefore \mathit{x}=5°$