LIC AAO 06 Mar 2016 Paper

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Question : 54 of 160

Marks: +1, -0

I .

x^2

= 10
II.

y^2

- 9y + 20 = 0

1
2
3
4
5

Solution:

i.

x^2

= 10 ⇒ X = ±

√{10}

ii.

y^2

- 9 + 20 = 0
⇒

y^2

- 5y - 4y + 20 = 0
⇒ y(y-5)-4(y-5)=0
⇒ (y - 4) (y - 5) = 0
⇒ y = 4 or, 5
Clearly, x < y

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