LIC AAO 05 Mar 2016 Paper

Question : 32 of 160

Marks: +1, -0

A certain sum is invested for 2 years in scheme A at 10% p.a. compound interest (compounded annually). Same sum is also Invested for 3 years in scheme B at x% p.a. simple interest. The interest earned from scheme A is half to that of earned from scheme B. What is the value of x ?

Validate

Solution:

C.I = P

[(1+R/{100})^T-1]

S.I. =

{P×R×T}/{100}

According to the question,
2

p[(1+10/{100})^2-1]

{Px×3}/{100}

⇒ 2

[(1+1/{10})^2-1]

{3x}/{100}

⇒ 2

[({11}/{10})^2-1]

{3x}/{100}

⇒ 2

({121}/{100}-1)

{3x}/{100}

⇒

{2×21}/{100}

{3x}/{100}

⇒ 3x = 2 × 21
⇒ x =

{2×21}/3

= 7 × 2 = 14

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