KVPY SX SB Exam 20141 Question Paper

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Question : 104 of 120

Marks: +1, -0

The equilibrium constants

(K_c)

of two reactions

H_2 + I_2 ⇌ 2HI

and

N_2 + 3H_2⇌2NH_3

are 50 and 1000, respectively. The equilibrium constant of the reaction

N_2 + 6HI ⇌2NH_3 + 3I_2

is closest to

50000
20
0.008
0.005

Solution:

H_2 + I_2 ⇌ 2HI;\;\;\;\;\;\;\;\;\;K_c = 50

N_2 + 3H_2⇌2NH_3;\;\;\;K_c =1000

_________________________________

N_2 + 6HI ⇌ 2NH_3 + 3I_2\;\;\;\;\; K_c =1000/(50)^3

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;K_c = 0.008

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