KVPY SX SB Exam 20141 Question Paper

Question : 103 of 120

Marks: +1, -0

The molar enthalpy change for

H_2O(1) ⇌ H_2O(g)

at 373 K and 1 atm is 41 kJ/mol. Assuming ideal behavior, the internal energy change for vaporization o f 1 mol of water at 373 K and 1 atm in kJ mol

^{-1}

Solution:

W = -nRT = -(1 × 8.314 × 10^{–3 }× 373)

kJ
= – 3.10 kJ

q = ∆H = 41

kJ
&

∆E = q + w = (41 -3.1) ≅ 37.9

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