KVPY SX SB Exam 2013 Question Paper

Question : 39 of 120

Marks: +1, -0

A point particle of mass 0.5 kg is moving along the x-axis under a force described by the potential energy V shown below. It is projected towards the right from the origin with a speed v.

What is the minimum value of v for which the particle will escape infinitely far away from the origin?

$2√2 \ms^{-1}$
$2 \ms^{-1}$
$4 \ms^{-1}$
The particle will never escape

Validate

Solution:

1/2\m\v^2+0=0+1

\v^2 = 4

\v = 2

m/s

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