KVPY SX SB Exam 2013 Question Paper

Question : 38 of 120

Marks: +1, -0

The average distance between molecules of an ideal gas at STP is approximately of the order of

Solution:

\n=\PV/\RT

={10^5×1}/{25/3×300}=40

N = 40 × 6.023 × 10^23

~ 24 × 10^24

Average sep.

=(1/\N)^{1/3}

≃ 1 nm

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