KVPY SA Exam 2011 Question Paper

Question : 9 of 80

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Three circles each of radius 1 touch one another externally and they lie between two parallel lines. The minimum possible distance between the lines is

$2+√3$
$3+√3$
4
$2+1/√3$

Validate

Solution:

\sin60°=\AD/2

\AD=2\sin60°={2√3}/2=√3

d = 1 + \AD + 1

d = 2 + √3

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