KVPY SA Exam 2011 Question Paper

Question : 8 of 80

Marks: +1, -0

In the adjoining figure AB = 12 cm, CD = 8 cm. BD = 20 cm; ∠ABD = ∠AEC = ∠EDC = 90°. If BE = x. then

Solution:

12/x={20-x}/8

⇒x^2-20x+96=0

⇒x=8,12

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