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Question : 37 of 120
Marks:
+1,
-0
Solution:
Given, line
r=2++t(3+−2‌)....(i)
and plane
2x+4y+az+8....(ii)
⇒‌‌(x+y+z‌)(2+4+a)=8 Since, given line, line (i) is parallel to plane (ii),
∴ n.
b=0 ⇒(2+4+a)⋅(3+−2)=0 ⇒6+4−2a=0 ⇒‌‌10−2a=0 ⇒‌‌a=5
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