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Question : 36 of 120
Marks:
+1,
-0
Solution:
Given line
r=+2+t(3+2−) and plane
2x−3y−z=1 ⇒(x+y+z‌)(2−3−)=1 ∴ Angle between line and plane
sin‌θ=| (2−3−).(3+2−) |
| |2−3−||3+2−| |
=‌=‌ ⇒‌‌θ=sin−1(‌)
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