KEAM 2015 Math Paper

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Question : 18 of 120

Marks: +1, -0

If x′+y′=1, then

yy′′+(y′)2+1=0
yy′′+2(y′)2+1=0
yy′′−2(y′)2+1=0
yy′′+(y′)2−1=0
yy′′−2(y′)2−1=0

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