© examsiri.com
Question : 17 of 120
Marks:
+1,
-0
Solution:
I=√π/22x3‌sin(x2)‌d‌x =√π/22x2⋅x‌sin(x2)‌d‌x Put
x2=t ⇒‌‌2xdx=dt Also, when
x=0, then
t=0 and when
x=‌, then
t=‌ ⇒‌‌I=‌sin‌‌d‌t =[t(−cos‌t)]0π/4−−cos‌t(1)‌d‌t =[−t‌cos‌t]0π∕4+cos‌t‌d‌t =[−t‌cos‌t+sin‌t]0π/4 =[−‌⋅‌+‌] =‌(1−‌)
© examsiri.com
Go to Question: