KEAM 2014 Math Paper

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Question : 18 of 120

Marks: +1, -0

Let A and B be two events such that

P(A∪B)=P(A)+P(B)−P(A)P(B).

If 0<P(A)<1 and 0<P(B)<1, then P(A∪B)′=

1−P(A)
1−P(A′)
1−P(A)P(B)
[1−P(A)]P(B′)
1

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