KEAM 2014 Math Paper

Total number of sample space,
n(S)=6×6=36
Let E= Event of getting maximum sum of two dices is 5
∴‌‌n(E)=12
∴ Probability (the maximum sum of two dices is 5)
=‌

n(E)

n(S)

=‌

12

36

=‌

5

3

∴ Probability (the sum of two dices is more than 5 )
=1− Probability (the sum of two dices is 5 )
=1−‌

1

3

=‌

2

3