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Question : 75 of 120
Marks:
+1,
-0
Solution:
Given lines are
‌=‌=‌ ‌=‌=‌.....(i)
and
‌‌‌=‌=‌....(ii)
since, both lines are perpendicular.
∴‌‌(1)(2)+(−1)(5)+(3)(p)=0 (by perpendicularity condition)
⇒‌‌2−5+3p=0⇒3p=3 ∴‌‌p=1
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